.sum of 2 no is 50 and sum of there reciprocal is 1/12. So find these number

• x+y=50
  1/x=1/y=1/12
  solving xy=600
  
  x+600/x=0
  solving x=20 or 30
  y=30 or 20
• 12 years agoHelpfull: Yes(10) No(1)
• numbers are 30 and 20....
• 12 years agoHelpfull: Yes(5) No(1)
• x+y=50
  1/x+1/y=1/12
  solving xy=600
  
  x+600/x=50
  solving x=20 or 30
  y=30 or 20
• 12 years agoHelpfull: Yes(4) No(1)
• x+y=50--->(1)
  (1/x)+(1/y)=(1/12)---(2)
  on rearranging (2) (x+y)/(xy)=(1/12)
  from(1)x+y=50
  therefore 60/(xy)=(1/12)
  on simplifying the above eqn (y^2)-50y+600=0
  on solving the above eqn the factors will be 20 and 30
• 12 years agoHelpfull: Yes(2) No(1)
• x+y=50
  
  1/x+1/y=1/12
  
  x+y/xy=1/12
  
  xy=50*12=600
  
  
  (x+y)^2=x^2+y^2+(2*xy)
  2500=x^2+y^2+1200
  =x^2+y^2=1300
  
  
  now (x-y)^2=1300-2(xy)
  =1300-1200
  =100
  x-y=10
  
  
  x+y=50
  x-y=10
  
  
  so x=30
  y=10
• 9 years agoHelpfull: Yes(1) No(0)
• x+y=50
  1/x+1/y=1/12
  solving xy=600
  
  x+600/x=50
  solving x=20 or 30
  y=30 or 20
• 10 years agoHelpfull: Yes(0) No(1)
• so there r two solutions na? either y=30 and x=20 / y=20 and x=30.?
• 10 years agoHelpfull: Yes(0) No(0)