In 10 years A will be twice as old as B was 10 years ago If A is now 9

it is 19
12 years agoHelpfull: Yes(8) No(3)
10 years after A's age will be (A+10)
10 years ago B's age was (B-10)
i.e. first equation will be --> A+10=2(B-10)
and second equation will be --> A=B+9
substituting second equation in first.
now, B+9+10=2B-20 => B=39
and A=48.
12 years agoHelpfull: Yes(4) No(0)
itz ans is 19.
12 years agoHelpfull: Yes(3) No(2)
39
a + 10=2(b-10)
a-b=9
12 years agoHelpfull: Yes(2) No(2)
let age of a is x n tht of b is y
hence,
x+10=2(y-10)
x=2y-20-10= 2y-30
now 2nd sttmt is :- x=y+9
2y-30=y+9
y=39 and x=48.
12 years agoHelpfull: Yes(2) No(2)
(a+10)=2(b-20)
a=b+9

solvng thm we get b=59
9 years agoHelpfull: Yes(0) No(1)
let their present age be x and y
ten year ago= x-10 and y-10
now, x+10=2(y-10)
x=9+y
by getting the values of x and y we get
x=48 nd y= 39 (by solving the given euatios)
9 years agoHelpfull: Yes(0) No(0)
a=2b
10 years ago,
a-10=2(b-10)
now, a=b+9
b+9-10=2(b-10)
ans is b=19
8 years agoHelpfull: Yes(0) No(0)
after 10 yrs. A's age will be (x+10) and 10 yrs. before B was (x-10) so the eqn 1become ....(A+10)=2(B-10)
since A is twice of B.
Second equation become A=(9+x) and B =x (since a is 9 years older than b)
so by putting the values of A and B we get A=48
7 years agoHelpfull: Yes(0) No(0)

. In 10 years , A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is: