What is the value of

44444445*88888885*44444442*44444438/44444448^2

a)88888883 b)88888884 c)88888888 d)44444443

• take x=44444444
  that equ.can be written as- (x+1) (2x-3) (x-2)+(x-6) / x^2
  solving equation we get 2x-5
  substitute x=44444444 in above equation we get- 88888883
  
• 9 years agoHelpfull: Yes(24) No(12)
• through digital sum concept::
  
  44444445= 33; 3+3=6
  88888885= 61; 6+1=7
  44444442= 30; 3+0=3
  44444438= 35; 3+5=8
  
  In numerator digital sum = 6*7*3*8 =1008 = 1+0+0+8=9
  In denominator digital sum =36=(3+6)^2 = 81; 8+1=9
  
  numerator /denominator = 9/9=1
  
  According to options 88888888 =8+8+8+8+8+8+8+8=64; 6+4=10; 1+0= 1
  
  see in question and answer option is same so C is correct..
  
  #GOPI
  
• 9 years agoHelpfull: Yes(11) No(13)
• 444444445*88888885*44444442*44444438=44444448*44444448*x
  Digital sum
  33*61*30*35=36*36*x
  6*7*3*8=9*9*x
  42*3*8=81*x
  6*3*8=9*x
  18*8=8*x
  9*8=9*x
  72=9*x
  9=9*x
  A)88888883 sum is 59
  5+9=14
  1+4=5
  9*x=9*5=45
  4+5=9
  Then 9=9
  Option A is correct ans
• 6 years agoHelpfull: Yes(0) No(1)