From 5 men and 11 women in how many ways can a panel of 11 be formal such that the

if we consider 0-men and 11-women case also den d ans comes 2256 ie (d).....guys should we consider dat case or not??
12 years agoHelpfull: Yes(12) No(0)
as we have to choose 3 men out of 5men...thn in tht case...options we have are..
5c3*11c8 + 5c2*11c9 + 5c1*11c10 + 11c11
hence final ans is 2256....i.e. none of these
guys dont get confused jst bcz of 1 digit...!!!
12 years agoHelpfull: Yes(9) No(2)
Just calculate the value of 5(M) 11(W) {condition not more than 3}
3 8
2 9
1 10
Just write the combinations now --->> 5C3*11C8+5C2*11C9+5C1+11C10=2255
12 years agoHelpfull: Yes(7) No(6)
2255 is the answer
12 years agoHelpfull: Yes(3) No(5)
its 2255
dnt consider the case of 5c0.11c11
12 years agoHelpfull: Yes(0) No(4)
5C3*11C8+5C2*11C9+5C1*11C10=2255
12 years agoHelpfull: Yes(0) No(2)
answer is option d(2256)
9 years agoHelpfull: Yes(0) No(0)
2256 is the right answer. As it is not in the option so ans is (d)None of these.
8 years agoHelpfull: Yes(0) No(0)

From 5 men and 11 women in how many ways can a panel of 11 be formal such that the number of the men is not more than 3.
a) 1650
b) 2255
c) 5522
d) None of these.