TCS
Company
consider a well of 100 mt depth and a frog at the bottom of the
well. It climbs 3mt in day time n slides down 2mt during night. How
many days it needs to climb the well?
Read Solution (Total 5)
-
- It Climbs 3 mts in Day & Slides Down 2 mts during Night => 3 - 2 = 1 m in One Day.
So Till 97 Days it reaches to 97 mts
but on 98th Day when it climbs to 3 mts, it reaches to the top i.e
97 + 3 => 100 mts
So Number of Days Required is 98 Days. - 12 years agoHelpfull: Yes(34) No(3)
- 97 is right answer because on 97th day frog climbs up 3mt an reach at top
- 12 years agoHelpfull: Yes(8) No(6)
- 97 days is the answer
- 12 years agoHelpfull: Yes(4) No(3)
- oye tcs ka wrtten test kese ho raha h kuch pata chala
? pls mail me ur questions to shyamleshd@gmail.com - 12 years agoHelpfull: Yes(0) No(4)
- how u solve.......any shortcut
- 12 years agoHelpfull: Yes(0) No(0)
TCS Other Question