. In a rectanglular coordinate system, what is the area of a triangle whose vertices whose vertices have the coordinates (4,0), (6, 3) adn (6 , -3)

• Given coordinates are(4,0),(6,3)and (6,-3).
  here base=3-(-3)=6
  height=6-4=2
  hence area=1/2*6*2=6(ans).
• 12 years agoHelpfull: Yes(10) No(0)
• After Drawing these point in graph, we will get two triangles:
  base is 2 & height is 3 for both the triangles .
  
  Triangle 1 Area => 1/2 * b * h => 1/2 * 2 * 3 => 3
  Triangle 2 Area => 1/2 * b * h => 1/2 * 2 * 3 => 3
  
  Area of Triangle 1 + Area of Triangle 2 => 3 + 3 => 6
  
  Answer is 6.
• 12 years agoHelpfull: Yes(8) No(1)
• let
  (4,0)=(x1,y1)
  (6,3)=(x2,y2)
  (6,-3)=(x3,y3)
  area=|[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]/2|=6 ans
• 12 years agoHelpfull: Yes(8) No(0)
• Ans will be 6 units...Because if you draw the figurse it will make base as 6 unit and height as 2 unit..now using the formula(1/2)*base*height ......it will be 6
  
• 12 years agoHelpfull: Yes(0) No(0)
• from the question the altitude of triangle is 2 units(6-4) and base is 6 units(3+3). so, area is 0.5*6*2=6 units
• 12 years agoHelpfull: Yes(0) No(0)
• the graph drawn by the given coordintes gives the value of altitude of triangle as 6-4=2 and base i given as 3 towards +ve y axix and 3 towards -ve y axis i.e3+3=6 so by formula : 1/2*2*6=6 ans.6
• 12 years agoHelpfull: Yes(0) No(0)