self
Maths Puzzle
in a sequence A(n) is defined by,A(1)=2 and A(n+1)=A(n)+2*n. find the value of A(200).
Read Solution (Total 3)
-
- A(1)=2; A(2)=4; A(3)=8; A(4)=14;A(5)=22; A(6)=32; A(7)=44 A(8)=58; it is clear that A(n)=A(1)+[(n)(n-1)]..........hence A(200)=A(1)+(200)(199)------>A(200)=2+39800=39802........So A(200)=39802
- 12 years agoHelpfull: Yes(4) No(0)
- A(199+1) = (2 + 2*1 + 2*2 + 2*3 +........2*199)
= 2(1 + (1 +2 + 3 +....+199))
= 2(1 + (199*(199+1)/2))
= 2 +199*200
=39802 - 12 years agoHelpfull: Yes(2) No(0)
- A(200)= 2+2(1+2+3+3+.......+199)=39802....
- 12 years agoHelpfull: Yes(0) No(0)
self Other Question