drawer hold 4 red hat and 4 blue hat.what is probabilty of getting exactly 3 red hatexactly 3 blue hatwhen taking 4 hat randomly out of drawer when immediately returning every haTto drawer before taking out of nextoption(a)1/2(b)1/8)(c)1/4(c)3/8)

• since you are picking a hat out of 4 red and 4 blue (equal number of both) & REPLACING it....we have exactly 1/2 chances of getting a red hat OR a blue hat.
  
  and then we replace the hat that is drawn...so
  
  the probability will always be 1/2=ans
• 12 years agoHelpfull: Yes(4) No(4)
• i think it should ne 1/8
• 12 years agoHelpfull: Yes(3) No(2)
• ans:1/2
  no of possible combinations=(4C1)^3*(4C1)*2
  sample space=8^3
  so ans is 1/2
• 12 years agoHelpfull: Yes(1) No(4)
• I think ans is 1/2
• 12 years agoHelpfull: Yes(0) No(2)
• sample space becomes=8*8*8
  p(E)=2(4c1*4c1*4c1)
  P(e)/p(s)=2*4*4*4/8*8*8=1/4
• 11 years agoHelpfull: Yes(0) No(0)