Three non integers numbers X, Y, Z are such that the mean is M and the median is 5. If M is 10 more that the smallest number and 15 less than biggest number, Find the values of X+Y+Z.
a) 15
b) 5
c) 20
d) 30

• we don't need individual values of x,y,z
  so let us consider x be smaller and z is larger
  so y is median=5
  mean=(x+y+z)/3=(x+z+5)/3
  mean=x+10 and z-15
  =>(x+z+5)/3=x+10 | (x+z+5)/3=z-45
  =>x+z+5=3x+30 | x+z+5=3z-45
  =>2x-z+25=0 ---(1) | 2z-x-50=0 ---(2)
  
  from the addition of two equations (1)+(2)
  =>(2x-z+25)+(2z-x-50)=0
  =>x+z-25=0
  =>x+z=25
  so x+y+z=(x+z)+y=25+5=30....
  
• 12 years agoHelpfull: Yes(43) No(2)
• we don't need individual values of x,y,z
  so let us consider x be smaller and z is larger
  so y is median=5
  mean=(x+y+z)/3=(x+z+5)/3
  mean=x+10 and z-15
  =>(x+z+5)/3=x+10
  =>x+z+5=3x+30
  =>2x-z+25=0 ---(1)
  and
  (x+z+5)/3=z-15
  =>x+z+5=3z-45
  =>2z-x-50=0 ---(2)
  from the addition of two equations (1)+(2)
  =>(2x-z+25)+(2z-x-50)=0
  =>x+z-25=0
  =>x+z=25
  so x+y+z=(x+z)+y=25+5=30....
• 12 years agoHelpfull: Yes(13) No(1)
• ans:30 median y=5 then (x=5=z)/3=x=10 and (x+5+z)=z-15 from thes two equations
  x+z=25 so x+y+z=25+5=30
• 12 years agoHelpfull: Yes(5) No(1)
• i think ans is 20
  
• 12 years agoHelpfull: Yes(3) No(14)
• x=m-10,y=m+15,x+y+z=3m,==>m-10+5+m+15=3m ==>m=10 ==>3m=30
• 12 years agoHelpfull: Yes(2) No(0)
• ans:30 median y=5 then (x=5=z)/3=x=10 and (x+5+z)=z-15 from thes two equations
  x+z=25 so x+y+z=25+5=30
• 12 years agoHelpfull: Yes(1) No(2)
• x,y,z here median is 5 take y as median...now suppose smallest no is 5...then M is 10 more then it is 15
• 12 years agoHelpfull: Yes(0) No(9)