: Peter and Paul are two friends. The sum of their ages is 35 years. Peter is twice as old as Paul was when Peter was as old as Paul is now. What is the present age of Peter?

• For these type of questions, use the formula 7x/4 =[sum of ages] where x is the age of elder.
  2)7x/3 = [sum of ages] whr x is the age of younger. Here peter is elder is 7x/4=35. Solve you get x= 20
• 14 years agoHelpfull: Yes(57) No(7)
• let peter=a paul=b
  given tat a+b=35,a=2(2b-a)
  3a=4b
  a=4/3b
  substituting v get a=20,b=15
• 14 years agoHelpfull: Yes(17) No(2)
• let peter=r
  paul=l
  peter was paul's age means r-l years ago
  r-l years ago peter was=r-(r-l)=l---->paul's age now
  r-l years ago paul was l-(r-l)=2l-r
  Peter is twice what Paul was
  r=2(2l-r)
  r=4l-2r
  3r=4l
  l+r=35
  3l+3r=105
  7l=105
  l=15
  r=20
• 14 years agoHelpfull: Yes(13) No(0)
• Let peter's age=x & paul's age=y
  Given: x+y=35
  Wen peter was as old as paul is now, i.e.
  wen peter was y i.e.(x-y) yrs ago,
  then paul was y-(x-y)=2y-x yrs old.
  so, acc. to condition:
  x=2* Paul's age x-y yrs ago,i.e.
  x=2(2y-x)
  x=4y-2x
  x=4(35-x)-2x
  x=140-6x
  7x=140
  x=20
  
  i.e. Peter's age is 20 yrs old.
• 12 years agoHelpfull: Yes(5) No(0)
• 15 & 20 z ans
• 14 years agoHelpfull: Yes(1) No(3)