x2 < 1/100
,
and x< 0 What is the tightest range in which x can lie?

-1/10 < x < 0
-1 < x < 0
-1/10 < x < 1/10
-1/10

• since x can have only a negative value...option c is out
  
  now x= -1/10 ...so any number like -1/11 will give x2=1/121 which is smaller than 1/100
  
  as we decrease the denominator we are approaching 0
  
  so the answer has to be option A
• 12 years agoHelpfull: Yes(39) No(7)
• -1/10 < x < 0
• 12 years agoHelpfull: Yes(29) No(7)
• given x2 < 1/100
  so, x < 1/10 or x > - 1/10 - first statement
  also, as per question x < 0 - second statement
  so, intersection of both statement will be
  - 1/10 < x < 0
  
• 9 years agoHelpfull: Yes(4) No(0)
• -1/10 < x < 0
• 12 years agoHelpfull: Yes(3) No(2)
• (x - a)(x - b) < 0 then value of x lies in between a and b.
  (x - a)(x - b) > 0 then value of x does not lie inbetween a and b. or ( −∞, a) and (b, −∞) if a < b
  x2 < 1/100 ⇒
  (x2−1/100)
• 9 years agoHelpfull: Yes(3) No(0)
• its A..
  x2 x
• 12 years agoHelpfull: Yes(2) No(2)
• X2
• 12 years agoHelpfull: Yes(1) No(11)
• -1/10
• 12 years agoHelpfull: Yes(1) No(7)
• We get x=-1/10
  And also x
• 10 years agoHelpfull: Yes(1) No(0)
• (x - a)(x - b) < 0 then value of x lies in between a and b.
  (x - a)(x - b) > 0 then value of x does not lie inbetween a and b. or ( −∞, a) and (b, −∞) if a < b
  x2 < 1/100 ⇒
  (x2−1/100)
• 9 years agoHelpfull: Yes(1) No(0)
• A) x have -ve value then
  check option 1 is suitable for above condition
• 9 years agoHelpfull: Yes(1) No(0)
• (x - a)(x - b) < 0 then value of x lies in between a and b.
  (x - a)(x - b) > 0 then value of x does not lie inbetween a and b. or (
  −
  ∞
  , a) and (b,
  −
  ∞
  ) if a < b
  x
  2
  < 1/100
  ⇒
  
  (
  x
  2
  −
  1
  /
  100
  )
  
• 6 years agoHelpfull: Yes(1) No(0)
• x2
• 10 years agoHelpfull: Yes(0) No(0)
• option b should be correct..as x= -1/10,in option a..x is greater than -1/10..it cant be equal..so technically b is the right answer
• 9 years agoHelpfull: Yes(0) No(0)
• x
• 8 years agoHelpfull: Yes(0) No(0)
• (x - a)(x - b) < 0 then value of x lies in between a and b.
  (x - a)(x - b) > 0 then value of x does not lie inbetween a and b. or ( −∞−∞, a) and (b, −∞−∞) if a < b
  x2x2 < 1/100 ⇒⇒
  (x2−1/100)
• 7 years agoHelpfull: Yes(0) No(0)
• -1/10
• 5 years agoHelpfull: Yes(0) No(0)