if x-y + z = 19 , y + z =20 , x-z=3 , find d value of x+4y-5z

• ANS: -13
  
  adding all, we get: 2x+z=42 and solving it with x-z=3, we get x=15, z=12 and y=8
  x+4y-5z = 15+32-60 = 47-60 = -13
• 11 years agoHelpfull: Yes(28) No(1)
• substitute y-z=20 in the 1st equation...i got x=15
  subs x=15 in 3rd equation...z=12
  subs x=15 and z=12 in 1st equation....y=8
  subs in question...i got ans=-13
• 11 years agoHelpfull: Yes(7) No(5)
• given x-y+z=19,y+z=20 add these two equations we get x+2z=39 and another equation given x-z=3 solve this equation and x+2z=39 we get x=15,put x=15 in x-z=3 get z=12
  put x=15 and z=12 in first equation we get y=8 so x+4y-5z=15+4(8)-5(12)
  15+32-60=-13 so -13 is answer
• 11 years agoHelpfull: Yes(4) No(0)
• ANS: 3
  
  adding all, we get: 2x+z=42 and solving it with x-z=3, we get x=15, z=12 and y=8
  x+4y-5z=15+48-60=3
• 11 years agoHelpfull: Yes(2) No(10)
• Ans : -13
  Hint : Solve 3 equations will get x=15,y=8,z=12
• 11 years agoHelpfull: Yes(2) No(1)
• adding eqn 2 and 3 we get x+y=23,add 1 and 3 we get 2x-y=22 add the two and you get x=15 y=-8 and z=12 and the final value is -77
• 10 years agoHelpfull: Yes(2) No(2)
• ans: -13....
• 11 years agoHelpfull: Yes(1) No(1)
• judt put the value ans is -13
• 7 years agoHelpfull: Yes(0) No(0)