If 28a+30b+31c=365 ,find the values of a+b+c if a, b, c are naturals numbers.
a) 4.
b) 12.
c) 10.
d) Cannot be determined.

• this ques is related to the no of days of a month in an ordinary(non leap) year.
  i.e.,28 days of feb(a=1);30 days of apr,jun,spt,nov(b=4) and 31 days of the rem months(c=7).hence a+b+c=1+4+7=12.so option B is correct
• 11 years agoHelpfull: Yes(57) No(3)
• the question is related to the no. od f days n month in an year...
  so it wil b lik..
  28*1 , 30*4 , 31*7
  hence, 1+4+7=12 is the answer
• 11 years agoHelpfull: Yes(11) No(3)
• ANS IS b=12
  28*2+30*1+31*9=365
  so,a=2,b=1,c=9
• 11 years agoHelpfull: Yes(4) No(6)
• 12
  
  no of months in a year.
• 11 years agoHelpfull: Yes(4) No(0)
• the no. of days in month in an year=12
  (non leap year)
  so it will be like
  28*1 , 30*4 , 31*7
  hence, 1+4+7=12 is the answer
• 11 years agoHelpfull: Yes(3) No(0)
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• 11 years agoHelpfull: Yes(2) No(0)
• ANS 12
  BCOZ IF WE ARRANGE ABOVE EQ 30(A+B+C)-2A+C=365 THEN IF WE TAKE A+B+C=12 THEN A=2
  B=1 & C=9 THEN ANSWER COMES CORRECT
• 11 years agoHelpfull: Yes(2) No(0)
• Check our calender
  where 7 month of 31 days
  4 month of 30 days
  1 28 days month
  so a + b + c = 12
• 9 years agoHelpfull: Yes(2) No(0)
• b) 12 here in ths question 28 - no of days in feb month... 30 and 31 are also no of days in month... total no of days in ayear is 365... hence the answer is 12
• 11 years agoHelpfull: Yes(0) No(1)
• b...if we take 365 days in a year no.of 28 is 1,no.of 30 days is 4,no.of 31 days is 7 ...total 12
• 8 years agoHelpfull: Yes(0) No(0)
• a=1
  b=4
  c=7
  there are 28 days in feb, so it is nt leap year.. count all 31 and 30 days of month..
• 7 years agoHelpfull: Yes(0) No(0)
• the answer is 12
• 6 years agoHelpfull: Yes(0) No(0)