10 years ago father was seven times as old as his son. 2 years hence twice his age will be equal to five
times his son. What is the present age of son?

• 14 years
  
  If 10 yrs ago, ages were s and f of son and father respectively, then
  f=7s
  2*(f+12)= 5*(s+12)
  
  solving it, we get
  s= 4 yrs
  present age of son = 4+10=14 yrs
• 11 years agoHelpfull: Yes(7) No(1)
• ans: sons age is 14
  sons present age = x
  fathers present age = y
  x-10 = 7*(y-10)
  2*(x+2) = 5*(y+2)
  solving these equations we get x = 38
  y = 14.
• 11 years agoHelpfull: Yes(2) No(2)
• consider,
  fathers present age=x
  son's present age =y
  then 10 years ago ,
  fathers age=x-10 & sons age =y-10
  from given, x-10 =7(y-10) ........................(1)
  & after 2 years
  fathers age is x+2 & sons age is y+2
  from given , 2(x+2) = 5(y+2) ............................(2)
  solving eqn (1) & (2) we get,
  y=14
  i.e. present age of son is 14 yrs
• 8 years agoHelpfull: Yes(2) No(0)
• son's age is 14 years
  father's age is 38 years
  explanation:::::
  let the age of son be x
  and father's age be y
  now according to 1st statement
  7(x-10)=(y-10)....................................(1)
  now according to second statement
  5(x+2)=2(y+2)...............................(2)
  by solving equation (1) and (2),we get
  x=14 =son's age
  y=38=father's age
  
  verify::
  7(14-10)=(38-10)=28....it verifies (1)statement.
  5(14+2)=2(38+2)=80....it verifies (2) statement.
• 8 years agoHelpfull: Yes(1) No(0)
• Let son's age 10 years ago be x yrs.
  thus,father's age be 7x yrs.
  2 yrs hence,father's age will be:7x+10+2
  son's age will be:x+10+2
  7x+12=5(x+12)
  x=24
  present age of son=24+10=34
  
• 11 years agoHelpfull: Yes(0) No(2)