R's age in 1994 is double the age of G, sum of R and G born years is 3844, wat s the age of R in 1999?

• If x is year of birth of R and y is year of birth of G, then
  
  x+y= 3844
  and
  (1994-x)= 2*(1994-y)
  
  solving it, we get
  x= 1898 and y = 1946
• 11 years agoHelpfull: Yes(25) No(3)
• if born year of r is R ,and g is G
  so R+G=3844
  and age of r in 1994 is double than that of g so we can write it as
  1994-R = 2(1994-G)
  1944-R = 2(1994-(3844-R)) from eq. (1)
  this eq give the value of R , R=1898 born year of r's so age of r in 1994 is 96 year and in ques they ask the age in 1999 so the anw is 101 year old....
• 11 years agoHelpfull: Yes(13) No(1)
• R is born in 1898 and G is born in 1946.
  
  Age of R in 1999 will be 101 years.
• 11 years agoHelpfull: Yes(6) No(0)
• ans. sould be 101,
  the sum of teir age is 3844
  so their born year sould be 1898 and 1946 so their total is 3844,
  now count the age of R from 1898 to 1994 it is 96 and G's age from 1946 to 1994 it is 48, and R's age in 1999 should be 101.
  
• 11 years agoHelpfull: Yes(3) No(0)
• Let, R's age in 1994 be x years.
  G's age= x/2 years.
  Now, Birth year of R =1994-x
  Birth year of G =1994-x+(x/2)
  
  Adding the above equations,
  (1994+x)+(1994-x+(x/2))=3844
  => x=96
  The age of R in 1994 is 96 years.
  So, The age of R in 1999 is=96+5=101 years
• 11 years agoHelpfull: Yes(1) No(0)