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a cylinder of dia 10 cm and a height of 20 cm s filled with water. if a sphere of dia is submerged inside the cylinder, what will be the increase in the level of water in the cylinder ?

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qstn is wrong since dia of sphere is not given
11 years agoHelpfull: Yes(12) No(4)

Initial vol. of Cylinder = pi*(R^2)*H1 = pi*25*20 = 500pi

Now, vol. of Sphere = (4/3)*pi*(R^3) = (500/3)pi ....(Diam have to be assumed as equal)

New vol. of cylinder = Initial cyc. vol + Sphere vol.
pi*25*H2 = 500pi +(1500/3)pi ..(since radius of cyc wil remain same)
Thus, H2 = 80/3

Now, dH = H2-H1 = 20/3 = 6.67
11 years agoHelpfull: Yes(7) No(3)

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