Find the value of lim(x tends to infinite) a^b

where a= 1+x^2
b= e^(-x)

• as e^(-x),x tends to infinite,so ans is 0
• 10 years agoHelpfull: Yes(0) No(1)
• Given that a=1+x^2 and b=e-(x),We have to find lim x->infinity (1+x^2)^e(-x) = lim-> infinity 1/(1+x^2)^e(x)= lim->infinity 1/(+x^2)^infinity=1/infinity=0.
  As we know that reciprocal of infinity is 0.So, 0 is the answer.
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• 1 is d answer
• 9 years agoHelpfull: Yes(0) No(0)