28a + 30 b +31c =365 find a+b+c if a.b.c are natural numbers

• ans is 1+4+7=12
  
  becoz in a year there are 7 months of 31 days and 4 months of 30 days and 1 month of 29 or 28 days so
  28*1+30*4+31*7=365
• 11 years agoHelpfull: Yes(93) No(0)
• as these are months in a calendar a=feb, b=jan,mar,may,jul,sep,nov ,c=apr,jun,aug,oct,dec ie a=1 b=6 c=5 hence a+b+c=12
• 11 years agoHelpfull: Yes(8) No(11)
• a =1,b =4, c=7 these are the months 1+4+7 =12
• 8 years agoHelpfull: Yes(0) No(0)
• 28, 30,31 represents days in a month a+b+c =12
• 5 years agoHelpfull: Yes(0) No(0)
• 28 is feb,30 is apr,jun,sep,nov.31 is jan,mar,may,jul,aug,oct,dec which means 28=1,30=4,31=7. so 1+4+7=12. answer is 12.
• 5 years agoHelpfull: Yes(0) No(0)