. A,B ,C can do some work in 36days.A and B together do twice as much work as c alone, and A and C together can do thrice as much work as B alone..find the time taken by C to do whole work?
a)96 b)108 c)120 d)72

• 1 day work for (A+B+C) = 1/36 ............(ii)
  Now, (A+B) = 2C ..........................(i)
  
  From (i)and(ii): 3C = 1/36
  C = 1/108
  
  Thus, C takes 108 days to complete the whole work alone.
  
  (Remaining data are not required in this case)
• 12 years agoHelpfull: Yes(37) No(5)
• AB:C
  2 :1
  total efficiency 1+2=3
  3 efficiency takes 36 days.i.e., ABC together takes 12 days
  1 efficiency take 36*3=108 days .i.e., C (whose efficiency is 1) takes 108 days.
• 8 years agoHelpfull: Yes(2) No(0)
• A+B+C->36
  A+B->2C ...let C do x amount of work then
  2/x+1/x=1/36
  x=108
• 10 years agoHelpfull: Yes(1) No(0)