In an year N, the 320th day of the year is Thursday. In the year N+1 the 206th day of the year is also Thursday. What is the 168th day of In the year N-1?
Options
o Friday
o Thursday
o Tuesday
o Saturday

• friday..If the Nth year is a non-leap year, then 320th day of year N to 206th day of year N+1 is [(365
  – 320) + 206] = 251 days i.e. 35 weeks + 6 days. But this will not make the two days to be
  Thursday.
  Thus, the Nth year has to be a leap year. In this case 320th day of year N to 206th day of year
  N+1 is [(366 – 320) + 206) = 252 days i.e. 36 weeks. Hence both days will be same day of the
  week i.e. Thursday as given by the data.
  
  168th day of N-1 year to 320th day of N year is [(365 – 168) + 320) = 517 days i.e. 73 weeks +
  6 days. Thus, if the 320th day is Thursday, then the 168th day of year will be Friday, option
• 12 years agoHelpfull: Yes(149) No(14)
• N: 320/7=45*7 + 5 => 5th day thursday . i.e, starting day of weak is sunday
  
  N+1: 206/7=29*7 + 3 => 3rd day is thursday . i.e, starting day is tuesday
  
  here we get 2 odd days,,,so it is a leap year....
  as (N+1)th Year is leap year, Nth, (N-1)th ,(N-2)th Can't be leap Years and so we will get 1 odd day for (N-1) th year.
  Starting Day in weak for (N-1) year is saturday....
  N-1: 168/7=28*7 => last day of the weak => Friday
• 12 years agoHelpfull: Yes(19) No(8)
• Friday...
• 12 years agoHelpfull: Yes(2) No(5)
• friday since
  320-206=114
  rem[114/7]=2
  therefore 206th day in N happens to be 2 days behind thursday i.e tuesday
  but in the year N+1 206th day = thursday which is 2 days after N+1 year 206th day
  therefore it proves N+1 is a leap year and since leap year occurs after 4 years is N and N-1 are npt leap year
  so 168th day in N-1 year is 1 day behind 168th day in N
  168th day in N= 320-168=rem[152/7]=5
  so it is 5 day behind 360th day i.e saturday
  so 168th day in N-1 is 1 day behind 168th day in N ie.
  168th day in N-1 year = friday
  
• 9 years agoHelpfull: Yes(1) No(0)
• As 320th day of the N th year and 206th day of the N+1 th are same day ,i.e, Thursday,
  there must be 0 odd days between these 2 days ( The number of days between these 2
  days must be divisible by 7)
  If N th is a non-leap year, the number of days between 2 days = (365 - 320 )+206 =251 days
  Here the number of odd days in 251 days is 6 =>So Nth year must be an ordinary year
  If Nth year is a leap , then the number of days between 2 days => (366 -320 ) + 206= 252 days
  Number of odd days in 252 days is 0 => So we can say that Nth year a leap year.
  To find the 168 th day of the year N-1, we have to find the number of odd days between the 320th day of Nth year and 168 th day of N-1 th year.
  => (365 -168) + 320 => 517 days
  The number of odd days in 517 => 6 odd days
  The 168th day of N-1 year is Thursday - 6 = Friday
• 4 years agoHelpfull: Yes(0) No(0)
• We know that Nth year is a non lap year, thus in the year N, the day 320 to the day 206 of the year N+1 is equal to:
  
  [(365 – 320) + 206] = 251 days = 35 weeks + 6 days = 36 weeks.
  
  Thus, we know that the day of the week is Thursday, then we have that both days will be in the same day of the week.
  
  We know that 168th day of N-1 year to 320th day of N year is:
  
  So, we conclude that in N-1 year, the day 168 to 320 of the year N is:
  
  [(365 – 168) + 320) = 517 days = 73 weeks + 6 days = 74 weeks.
  
  Thus, if the day 320 is Thursday, we can conclude that the day 168 of the year will be Friday.
  
  Hence, the valid answer is A) Friday.
• 5 Months agoHelpfull: Yes(0) No(0)