a cow is sold at a profit of 20% and hourse at loss of 10%. The overall gain is 4000. the cost price of cow and hourse is 200000. find cost price of cow

• let cost price of cow is x
  then cost price of horse is (200000 - x)
  according to the question,
  1.2*x + (200000 - x)*0.9 = 204000
  solving this we get
  x = 80000
  so cost price of cow is 80000
• 10 years agoHelpfull: Yes(17) No(0)
• c+h=200000,
  (120/100)c+(90/100)(200000-c)=204000,
  c=240000/3=80,000
• 10 years agoHelpfull: Yes(2) No(0)
• let price of cow is x
  then price of horse is (2,00,000-x)
  
  so as per the question (1.2x+.9(2,00,000-x))=2,04,000
  or, x=80,000
  
  so the price of cow is 80,000
• 10 years agoHelpfull: Yes(1) No(1)
• given: x+y=200000. let the c.p of cow be x and the horse be (x-2,00,000)
  20% of x + 10% of (x - 200000) = 4000( gain)
  x/5 + (x - 200000)/10 = 4000
  3x/10 = 4000 + 200000 = 2,40,000
  x= 80,000
• 10 years agoHelpfull: Yes(1) No(1)
• 80000--->2/5*200000
• 10 years agoHelpfull: Yes(1) No(0)
• let cost price of cow is X
  let cost price of HORSE is Y
  OVERALL GAIN IS (1.2X+0.9Y)-(X+Y)=4000
  AND X+Y=200000
  AFTER SOLVING
  X=80000
  
• 10 years agoHelpfull: Yes(1) No(0)
• let the c.p. of cow be Rs.x, then the c.p. of horse is Rs.(200000-x)
  20% of x-10% of (200000-x) = overall gain
  20*x/100-x/100*(200000-x)=4000
  30x-2000000=400000
  30x=2400000
  x=2400000/30
  x=80000
  Thus, c.p. of cow = Rs. 80000
  
• 10 years agoHelpfull: Yes(0) No(0)
• c.p=200000
  profit=4000
  let c.p of cow =x
  c.p of horse=200000-x
  profit=s.p-c.p
  s.p of cow=0.2x+0.9(200000-x)
  4000=.2x+.9(200000-x)-200000
  solving above equation,we get
  x=80000
  
• 10 years agoHelpfull: Yes(0) No(1)
• Let c.p. of cow is x
  then c.p. of horse is (200000-x),
  profit %=100+20/100=1.2,loss%=100-10/100=0.9,
  overall gain=4000,
  solving this we get the answer is
  (1.2*x)+(200000-x)*0.9=204000,
  x=80000.cp of cow is 80000
• 10 years agoHelpfull: Yes(0) No(0)
• Let Cow cost price is X.COst price of Horse is Y.
  He mentioned that X+Y=200000
  Y=200000-x
  Cow is sold at a profit of a 20% So 20% of x becomes 0.2x
  Horse is sold at a loss of 10% so 10% of Y becomes 0.1y.
  0.2X-0.1Y=4000
  0.2X-0.1(200000-x)=4000
  0.2X-20000+0.1X=4000
  0.3X=4000+20000
  X=8000/-
  
• 10 years agoHelpfull: Yes(0) No(2)
• ans: 80,000
  
• 9 years agoHelpfull: Yes(0) No(0)
• overall gain=s.p -c.p
  4000=(90(200000-x)/100)+(120x/100)-(200000)
  30x/100=204000
  x=80,000
• 9 years agoHelpfull: Yes(0) No(0)
• 1.2(cow)+0.9(horse)=200000-4000=196000.
  then
  price of cow is [(196000)/(2.1)]*(1.2)=rs1,12,000 /-
  price of horse is [(196000)/(2.1)]*(0.9)=rs 84000/-
• 9 years agoHelpfull: Yes(0) No(0)
• vinisha.vinz@gmail.com
• 9 years agoHelpfull: Yes(0) No(0)