exam
Maths Puzzle
Numerical Ability
(3x+5)*2x-2/3x^2+2x-5
I see that I would cancel out the 2x can I cancel out the 3x?
(3x+5)*-2/3x^2-5
I am confused can you help?
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exam Other Question
How would you multiply this binomial?
(4c-1)^2
I came up with 16c^2-8c+1... is that correct... or is it 16c^2+8c+1?
(radical x-1) = x-3