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Maths Puzzle
if both 11^2 and 3^3 are the factors of the number a*4^3*6^2*13^11,then what is the smallest value of a?
options:
a)121
b)3267
c)363
d)33
Read Solution (Total 3)
-
- 11^2 is not a factor of 4^3*6^2*13^11
so we add 11^2 to it. i.e:121
in 3^3 3 is the factor of 6 in 6^2.
6^2 can be wrriten as 3^2*2^2.
so we have 2 3's already so. we need only one 3 from 3^3
so:
121*3=363 - 9 years agoHelpfull: Yes(1) No(0)
- c>363 (11^2*3)
- 10 years agoHelpfull: Yes(0) No(0)
- DEBANU DAS ...explain the ans??
- 10 years agoHelpfull: Yes(0) No(0)
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