Find two consecutive even integers so that three times the smaller is 40 more than two times the larger.

• the numbers are 42 , 43
  let the two consecutive numbers be a & a+1
  3a = 2(a+1) + 40
  3a = 2a +42
  a=42
  a+1 = 43
• 9 years agoHelpfull: Yes(0) No(0)