The remainder of
(1234567890123456789)^24 is divided by 6561?

• Ans: 0
  (1234567890123456789) is divisible by 9
  So (1234567890123456789)^24 also divisible by power of 9 less than equal to 24
  6561 is divisible by 9(9^4=6561) Thus remainder:0
• 11 years agoHelpfull: Yes(4) No(0)
• last three digits=7,8,9=7+8+9=24 is divisible by 3 so the no.is divisible by 9
  so rem = 0
• 10 years agoHelpfull: Yes(0) No(0)
• 6561...only divided on 3 and 9..
• 9 years agoHelpfull: Yes(0) No(0)
• It is of the form (N^24)/P where N & P are divisible by 9...Hence P divides N completely without leaving any remainder. therefore Remainder=0
• 7 years agoHelpfull: Yes(0) No(0)