find probability of the leap year choosen at random will have 53 sundays

• plzz some body help...i m already applied in tcs bt not getting any mail for online test which is going to be held on 20 feb 2015.plzz help me
  
• 9 years agoHelpfull: Yes(15) No(0)
• leap year=366 days
  52 week=364 days
  so 52 sundays are there
  now from 366 days 2 days are left
  ex...it can be combination of any two days
  thats why probability is=2/7
• 9 years agoHelpfull: Yes(12) No(0)
• Miss Annu Priya you may contact to the tcs potal on helpline given below from where u login to ur account.
  
• 9 years agoHelpfull: Yes(3) No(0)
• let us consider,
  leap year=366 days. 52 weeks+2 days.
  n(A)=Event having 53 sunday=Week contain 7 days,n(S)=7
  combination having sunday={SM,MT,TW,WT,TF,FS,SS} i.e.n(A)=2
  P(A)=n(A)/n(S)=2/7.
• 9 years agoHelpfull: Yes(3) No(0)
• 2/7 bcz leap year contains 366 days i.e (52 weeks +2days) hence to have 53 sundays we have the probability (1/7+1/7=2/7)
• 9 years agoHelpfull: Yes(1) No(0)
• answer is 2/7.
• 9 years agoHelpfull: Yes(0) No(0)
• 52 week=364 days
  52 sundays are there in 52 weeks
  leap year has 366 days
  366-364=2
  so it shud be 2/7 is the answer
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• the most common probability problem in the whole world.... it will always be 2/7 if a leap year is considered having 53 mondays, tuesdays, wednesdays, thursdays, fridays, saturdays or sundays...
• 9 years agoHelpfull: Yes(0) No(0)