If 30 men working 7 hours per day can do a work in 18 days in how many days will 21 men working 8 hours a day do the same work?

• for these problems follow the formulae ((M1)*(D1)*(H1))/(W1)= ((M2)*(D2)*(H2))/(W2)
  
  WHERE M- men or women
  H- hours
  D-days
  W- work
  here work is same .therefore W1=W2
  M1*D1*H1=M2*D2*H2
  
  30*7*18=21*8*x
  
  implies X=22.5 days
  
• 11 years agoHelpfull: Yes(29) No(0)
• time taken=22.5 days
• 11 years agoHelpfull: Yes(12) No(1)
• m1t1d1/w1=m2t2d2/w2 ...w1=w2{same work}then d2=m1t1d1/m2t2
  30*7*18/21*8=d2...ans=45/2=22.5
  
• 11 years agoHelpfull: Yes(4) No(0)
• m1*d1*h1=m2*d2*h2
  30*7*18=21*d2*8
  by solving we get 22.5 days
• 11 years agoHelpfull: Yes(4) No(0)
• 30men 7hrs 18 days
  1men 7hrs 18/30days
  1men 1hrs 18/(30*7)days
  21men 8hrs 18*21*8/(30*7)=14.4days
• 11 years agoHelpfull: Yes(1) No(22)
• Formula
  P1*H1*D1=P2*H2*D2
  here
  P=person
  H=hours
  D=number of days
  30*7*18=21*8*x
  x=(30*7*18)/(21*8)
  x=22.5 days
• 5 years agoHelpfull: Yes(1) No(0)
• 280 seconds
• 8 years agoHelpfull: Yes(0) No(0)
• M1*d1*h1=m2*d2*h2
  So, 30*7*18=21*d2*8
  d2=45/2=22.5
• 4 years agoHelpfull: Yes(0) No(0)