Totally 3 beakers A,B,C are present. A of capacity X lit, B of capacity 2X lit,C of capacity 3X lit. if A contain 2/3 of wine and rest with water. B contains 1/4 of wine and rest with water. if these two liquids are poured in to the 3rd beaker what is the proportion of wine in the 3rd beaker.

• Let, A's capacity =30 litre
  B's capacity = 60 litre
  C's capacity = 90 Litre.
  
  A contain wine = 20 Litre
  B contain wine = 15 Litre
  
  so, Total wine in C = 20+15=35 litre
  
  Proportion=35/90=7/18
• 12 years agoHelpfull: Yes(27) No(2)
• A contains (2/3)*x lt.wine(7/6)*x
  B contains (1/4)*2x lt. wine and (3/4)*2x lt. water
  if we mix both we will get 3x lts of solution and in that
  wine=[(2/3)*x]+[(1/2)*x]=(7/6)*x lt
  so proportion of wine=(7/6)*x/3x=7/18....
  
• 12 years agoHelpfull: Yes(24) No(3)