16)There are 5 men and 11 women. How many ways can a panel of 11 be formed such that the number of men is not more than 3.

• 5C0*11C11+5C1*11C10+5C2*11C9+5C3*11C8=2256
  
• 12 years agoHelpfull: Yes(73) No(1)
• 5C0*11C11+5C1*11C10+5C2*11C9+5C3*11C8=2256
  Number of men not more than 3,so either 0 or 1 or 2 or 3 men can be selected....and to form 11 member panel 11,10,9,8 women selected respectively.
• 12 years agoHelpfull: Yes(31) No(0)
• we can select men is not more than 3 in following 4 ways
  3m and 8 women =5C3*11C8
  2m and 9 women =5C2*11C9
  1m and 10 women =5C1*11C10
  0m and 11 women =5C0*11C11
  Add these ans is =2256
• 12 years agoHelpfull: Yes(23) No(0)
• 5C0*11C11+5C1*11C10+5C2*11C9+5C3*11C8=3906
• 12 years agoHelpfull: Yes(5) No(15)
• ans is 175.
  3 men can be selected out of 5 is 5C3=10
  8 woment can be selected out of 11 is 11C8=165
  so a panel of 3 men and 8 women, totally 11 members can be selected in 175 different ways
• 12 years agoHelpfull: Yes(4) No(28)
• we can select men is not more than 3 in following 4 ways
  3m and 8 women =5C3*11C8
  2m and 9 women =5C2*11C9
  1m and 10 women =5C1*11C10
  0m and 11 women =5C0*11C11
  Add these
  
• 12 years agoHelpfull: Yes(2) No(4)
• can anyone tel me the correct ans :??????? plz i think 175 is the ccorrect
• 12 years agoHelpfull: Yes(0) No(24)
• none of these
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• 11C3=1706 11*10*9/2*3
• 8 years agoHelpfull: Yes(0) No(0)
• 5C3*11C8= 1650
  5C2*11C9= 550
  5C1*11C1= 55
  5C0*11C11=1
  Therefore, 1650 + 550 + 55 + 1 = 2256
  
• 8 years agoHelpfull: Yes(0) No(0)
• we can select men is not more than 3 in following 4 ways
  USE this formula for easy calculations => nCr=nCn-r
  3m and 8 w =5C3*11C8=5C2*11C3=1650
  2m and 9 w =5C2*11C9=5C2*11C2=550
  1m and 10 w =5C1*11C10=5C1*11C1=55
  0m and 11 w =5C0*11C11=5C0*11C0=1
  Add all these =1650+550+55+1=2256 (ans is-> 2256)
• 6 years agoHelpfull: Yes(0) No(0)