If 2y cos theta=x sin theta and 2x sec theta -y cosec theta=3, then the relation between x and y is

• x/y=2cot@
  let theta =@;
  2y cos@=x sin@...(a)
  2y=x sin@*sec@;
  2y cosec@=x*sec@....(1)
  2x sec@-ycosec@=3...(2)
  put the value of x sec@...
  4ycosec@-ycosec@=3
  3ycosec@=3
  y=sin@ =>put the value in (a)
  x=2cos@
• 12 years agoHelpfull: Yes(1) No(3)
• relation between x and y is y^2+(x^2)/4=1
• 12 years agoHelpfull: Yes(1) No(1)