How many natural number not exceeding 4321 can be formed with the digits 1,2,3 and 4 if the digits can repeat.

(PLEASE GIVE PROPER EXPLANATION)

• wen 1 in thousand place.other three place can b fill 4*4*4=64.
  same 2 and 3.till now(64+64+64)=192.
  nex wen 4 in thousand place and 1 in hundred place,rest two place we can fill(4*4) way.and same wen 2 will b hundred place,so till now total(192+16+16)=224.
  now wen 3 in hundred place and 1 in ten place we can fill rest one place by 4 way.and 2 in ten place we can fill rest one place by only 1 way....so total ans is(224+4+1)=229.
• 12 years agoHelpfull: Yes(5) No(4)
• 1 digit no = 4
  2 digit no. = 4^2= 16
  3 digit no = 4^3 = 64
  4 digit no = keepng 1 at thousnd place= 4^3= 64
  keepng 2 " " " = 4^3=64
  " 3 " " " =4^3= 64
  " 4 " " " = (16+16+4+1)=37
  4 digit no's =64+64+64+37=229
  total numbers possible =229+64+16+4 = 313 :)
• 12 years agoHelpfull: Yes(4) No(4)
• ans is 4*3*2*1=24
• 12 years agoHelpfull: Yes(0) No(5)
• how??????????????????????????????????????
• 12 years agoHelpfull: Yes(0) No(0)
• Thanx.................
• 12 years agoHelpfull: Yes(0) No(0)
• @akshay
  
  I dont understand from this :-
  
  " 4 " " " = (16+16+4+1)=37
  4 digit no's =64+64+64+37=229
  total numbers possible =229+64+16+4 = 313 :)
• 12 years agoHelpfull: Yes(0) No(1)