X takes 4 days to complete one-thrid of a job,Y takes 3 days to complete one-sixth of the same work and
Z takes 5 dyas to complete half the job.If allof them work together for 3 dyas and X and Z quit,how long
will it take for Y to complete the remaining work done.

• x takes 4 days to complete 1/3 rd of the job so
  x's work per day is 1/12 and for 3 days =1/4
  similarly
  y's work per day is 1/18 and for 3 days =1/6
  z's work per day is 1/10 and for 3 days =3/10
  
  if all work together their 3 days work=1/4 + 1/6 + 3/10
  =(15+10+18)/60 =43/60 work is done
  remaining work=1-(43/60)=17/60
  for 17/60 th work y takes (17/60)*18= 5.1 days...
  [ since y's work per day is 1/18 so y completes the total work in 18 days]
  
  so the answer is 5.1 days...
• 12 years agoHelpfull: Yes(30) No(0)
• Y will take another 5.1 days to complete the work
  
  if the options dont have 5.1, then its 6 days!
• 12 years agoHelpfull: Yes(5) No(4)
• x's 1day work = 1/12
  y's 1days work = 1/18
  z's 1 day work = 1/10
  x+y+z's work in 1 day=1/12+1/18+1/10=43/180.
  for three days=43*3/180=43/60.
  left over work=17/60.
  now wen y has to finish 17/60 of work alone.
  and since y's 1 day work is 1/18,
  (1/18)*x=17/60.where x is the no. of days to finish the work by y alone.
  hence x=5.1 days
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• hi buddy mail me few ques plzzz i have tcs in my college this week end mayur_leo247@yahoo.com
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• can you explain it
  
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