CTS Company Numerical Ability Number System

The sum of three consecutive numbers of 4 digits A,B,C and D are 4613,4961,5010 and 5099, then what is the largest number among A,B,C,D?

Read Solution (Total 2)

A+B+C = 4613
B+C+D = 4961
C+D+A = 5010
D+B+A = 5099

add four eqns

3(A+B+C+D) = 19683
=> A+B+C+D = 6561

so, largest no. = (A+B+C+D) - (A+B+C) = 6561- 4613 = 1948
9 years agoHelpfull: Yes(32) No(4)

add all A+B+C+D/4=6561
6561-4613=1948
6561-4961=1600
6561-5010=1551
6561-5099=1462
among these 1948 is largest number
7 years agoHelpfull: Yes(0) No(0)

CTS Other Question

Megha drives along the perimeter of square field of side 10 kms. She drives along the first side at 10 kmph, along the second side at 20 kmph, along the third side at 30 kmph and along the fourth side at 40 kmph. Her average speed is If X^Y denotes X raised to the power of Y, find out last two digits of
(2957^3661) + (3081^3643)