Megha drives along the perimeter of square field of side 10kms.She drives along the first side at 10kmph.along second side 20 kmph along 3rd side 30kmph and along the forth side at 40 kmph.Her avearse speed is ?
19.2kmph ,18kmp,30kmph,20kmph

• Average speed : total distance/total time
  Total distance=10*4=40 km
  total time =10/40 + 10/20 + 10/30 + 10/40
  
  So, Average Speed = 19.2 Km/h
• 12 years agoHelpfull: Yes(29) No(1)
• average speed =4/1/10+1/20+1/30+1/40 =19.2
• 12 years agoHelpfull: Yes(21) No(7)
• Average speed : total distance/total time
  Total distance=10*4=40 km
  total time =distance/speed=10/10 + 10/20 + 10/30 + 10/40=1+(1/2)+(1/3)+(1/4)=(25/12)=2.0833
  therefore avg speed=(40/2.0833)=19.20kmph
  
• 12 years agoHelpfull: Yes(9) No(0)
• avg speed=total dist/total time
  total dist=10*4=40
  total time=10/40+10/30+10/20+10/10=25/12
  avg speed=40/(25/12)=19.2kmph
• 12 years agoHelpfull: Yes(7) No(0)
• ans 19.2 kmph
• 12 years agoHelpfull: Yes(5) No(1)
• APPLying 2xy/xy thrice we can get the answer as 19.2
• 12 years agoHelpfull: Yes(2) No(3)
• total time = (10/10+10/20+10/30+10/40)=25/12
  total distance =40
  avg.speed =40(12/25)=19.2
• 5 years agoHelpfull: Yes(1) No(0)
• Average speed : total distance/total time
  Total distance=10*4=40 km
  total time =10/10 + 10/20 + 10/30 + 10/40
  
  total time=2.08
  speed=40/2.08
  So, Average Speed = 19.23 Km/h
• 8 years agoHelpfull: Yes(0) No(0)
• Average speed : total distance/total time
  Total distance=10*4=40 km
  total time =10/40 + 10/20 + 10/30 + 10/10=2.0833333....
  ave speed=40/2.083
  
  So, Average Speed = 19.2 Km/h
• 8 years agoHelpfull: Yes(0) No(0)