A can do some work in 24 days B can do it 32 days and C can di it in

A does 1/24 work in one day =1/24*6=0.25 work in 6 days
B does 1/32 work in a day =1/32*8=0.25 work in 8 days
work left =0.5
c does 1/60 work in one day =0.0166
to do 0.5 work it takes =0.5/0.0166=30 days
12 years agoHelpfull: Yes(4) No(10)
a does 1/24 work, b does 1/32 work for a day,
so the work done by a and b before they leave is 6/24 +8/32 = 1/2
so the remaining work to be done is 1/2 this can be done by c in 30 days
but as the 3 started together c continued with b upto 8 days so c should do 22 days work extra. so total days taken is 30 days and number of more days to be worked is 22
12 years agoHelpfull: Yes(3) No(1)
all work together=1/24 + 1/32 +1/60 = 43/480
all work together for 6 days = 43/480 * 6 = 43/80
now b leaves after 8 days that means 8-6 = 2 days b and c work together
b and c work together = 1/32 + 1/60 = 23/480
b and c work together for 2 days = 23/480 *2 = 23/240
work remains = 1-(43/80 + 23/240) = 11/30
since 1 work is done by c in 60 days
so 11/30 work is done by 60 * 11/30 = 22 days
8 years agoHelpfull: Yes(1) No(0)
Total work= lcm of(24,32,60)=480 units

One day work done by

A=24*20=480 so,20 unit/day
Similarly
B=15u/day
C=8unit/day

They work 6 days together

(20+15+8)*6=258unit

A left

B left (8-6)=2 days after A left

(15+8)*2=46unit

Total left(480-258-46)=176 unit left

176unit done by C

=176/8=22 days

Enjoy......
8 years agoHelpfull: Yes(1) No(0)

A can do some work in 24 days,B can do it 32 days and C can di it in 60 days.They start working together.A left after working for 6 days and B left after working for 8 days.How many more days are required to complete the whole work???
22,25,20,30
Ans=30 days