IN THIS SEQUENCE 1 22 333 4444 11 2222 333333 44444444 111 222222 ........... what is 2926th term???

• given sequence is of interval 4
  2926/4 = results 731 and remainder is 2
  i.e 731 sequences of group 4 is completed
  reminder 2 tell that next term is 732 times 1 and 1464 times 2
  so answer is
  2 occuring 1464 times
• 11 years agoHelpfull: Yes(29) No(4)
• 1 2 3 4 = 10
  2 4 6 8 = 20
  10+20+30+40......=2926
  10(1+2+3+4+...)=2926
  10(n(N+1)/2)=1296
  n = 23.03
  2926th term is 4
• 11 years agoHelpfull: Yes(16) No(26)
• 2 occurs 1464 times
  2926mod4= 2 so 732th block will start
  in every block nu,ber of 2's are incremented by 2 so 732*2= 1464 2's
• 11 years agoHelpfull: Yes(9) No(1)
• 2 occur 732 times is d answer
• 11 years agoHelpfull: Yes(5) No(9)
• IN THIS SEQUENCE 1 22 333 4444 11 2222 333333 44444444 111 222222 ……….. what is 2926th term
  
  1 22 333 4444 has 10 terms; 11 2222 333333 44444444 has 20 terms; Like this we will have 30, 40, 50 terms…Please note that in the first 10 terms, the last four terms are all ‘4’, and in the next 20 terms the last eight terms are all ‘4’ .
  
  Let 3000 be the sum of 10. 20, 30,…terms. The number of terms that will give this total of 3000 is given by the formula: n[2a +(n-1)d]/2. We have 3000 = n[20 + (n-1)10] /2 Or 6000 = n(10n +10) or 600 = n(n+1); or n = 24. In other words, if 10 is the first term, 20 is the second term then the 24th term will be 240.
  
  We see that in 10 terms there are four ‘4’; hence in 240 terms there will be ninety six ‘4’. Hence from 3000-96 till 96 we will have nothing but ‘4’s only. i.e, from the 2904th term, we have nothing but ‘4’ only. Hence the 2926th term is 4.
  
• 8 years agoHelpfull: Yes(5) No(0)
• 222222...upto 1462term
• 11 years agoHelpfull: Yes(4) No(2)
• (1 22 333 4444) (11 2222 333333 44444444)
  10 + 20 + 30 +40 - - - - - - - - - - - - -consider (290)
  the number of terms in the given question are in AP,so the a+(n-1)d = 10+(290-1)10 =2900
  for 10 we have 1 1's
  for 20 we have 2 1's
  like wise for 290 we have 29 1's
  and next term will be have 30 1's
  so 2900 ends with 4
  now upto 2930 all digits are 1's
  and 2926th term also will be 1
  hope you understood...
  
• 8 years agoHelpfull: Yes(2) No(0)
• see the given sequence is after interval 4
  2926/4 = results 731 and reminder is 2
  i.e 731 sequences of group 4 is completed
  reminder 2 tell that next term is 732 times 1 and 732 times 2
  so answer is
  2 occur 732 times is d answer
• 11 years agoHelpfull: Yes(1) No(7)
• answer is 2. bcoz 732 times 1 and 1464 times is 2
  
• 8 years agoHelpfull: Yes(1) No(0)
• can u give me a detailed explanation plz.
• 11 years agoHelpfull: Yes(0) No(3)
• total grandtotal
  1 2 3 4 10 10
  2 4 6 8 20 30
  4 8 12 16 40 70
  8 16 24 32 80 150
  16 32 48 64 160 310
  32 64 96 128 320 630
  64 128 192 256 640 1270
  128 256 384 512 1280 2550
  256 512
  
  we want 2926th term so 2926-2550=376
  in 256 there will be 1's after there will be 2 so 2926th term will be 2
• 8 years agoHelpfull: Yes(0) No(0)