28a + 30 b +31c= 365 find a+b+c if a.b.c are natural numbers.

• Since 365 is the total number of days in a year(please note not a leap year) we calculate the number of months having 30 and 31 days. We know Feb has 28 days so
  a=1,b=4 and c=7. b=4 because there are four months having 30 days and c=7 because there are 7 months which are of 31 days each. Hence the values.
• 12 years agoHelpfull: Yes(32) No(1)
• It was jst like d months in a year(assume)...
  non-leap year with 365 days...
  28(1month)+30(5 months)+31(6 months) = 365days...
  1+5+6=12...
• 12 years agoHelpfull: Yes(11) No(4)
• ans is 12...
• 12 years agoHelpfull: Yes(2) No(2)
• 365 is the no of days in year and a,b,c represent number of months having 28 ,30and 31 days hence a+b+c=12
  
• 12 years agoHelpfull: Yes(2) No(1)
• 12
  
  28a + 30 b +31c= 365
  
  a=2
  b=1
  c=9
  
  a+b+c=12
• 12 years agoHelpfull: Yes(2) No(0)
• agree with the anushka's answer total is 365 thanx
• 12 years agoHelpfull: Yes(1) No(1)
• can you explain how 12 comes pleaseeee
  
• 12 years agoHelpfull: Yes(0) No(1)