Points A and B move with uniform speed along straight lines that intersect at right angles at point O. When A is at O, B is 400m from O. After 3 minutes they are equidistant from O. After 5 more minutes, they are again equidistant from O. Then the ratio of A's speed to B's speed is

• If their speeds are a nd b respectively, then
  3a= 400-3b
  8a= 8b-400
  
  solving these eqns, we get
  a=250/6 m/min and b = 550/6 m/min
  ratio a/b = 250/550 = 5/11
• 11 years agoHelpfull: Yes(18) No(18)
• sai to likha kar re
• 11 years agoHelpfull: Yes(0) No(3)
• 5:13
  ( let after first 4 minutes OA=BO = x
  Speed of A= x/4
  B covers (300-x) in first 4 minutes.
  Speed of B = (300-x)/4 =
  75-(x/4)
  in next 5 minutes A goes 5x/4. After 9 minutes A goes (x+(5x/4)) = 9x/4
  After 9 minutes OA = 9x/4
  i.e. After 9 minutes OB should be 9x/4
  In next 5 minutes B goes (x+9x/4) = 13x/4
  
  i.e. 5(75-(x/4)) = 13x/4
  i.e. x = 250/3
  
  speed of A = 250/12
  speed of B = 75-(250/12) = 650/12
  speed of A/speed of B = 5/13
  )
• 6 years agoHelpfull: Yes(0) No(0)