Test on three subjects Physics, Chemistry & Biology are to be conducted simultaneously the number of candidates for the tests are 68, 36 and 72 respectively. Candidates are to be seated in different rooms such that each room will have candidates of the same subject and the load on each invigilator be the same i.e. the number of candidates in each room should be the same what is the minimum number of rooms you need for the purpose.

a) 22
b) 30
c) 44
d) None of these

• hcf(36,68,72)=4
  so 4(9+17+18)=44
  ans :44
• 9 years agoHelpfull: Yes(5) No(0)
• ans is 44
  first divide with 2 we get 78
  with 3 cnt divide
  divide 68,36,72 with 4 we get 17,9,18=17+9+18=44
• 9 years agoHelpfull: Yes(3) No(1)
• Ans-44
  first take HCF which is =4
  than divide the sum by HCF = (72+36+68)/4=176/4=44
• 8 years agoHelpfull: Yes(2) No(0)
• 68+36+72= 176
  divide it with 3(i.e 176/3) ., which dont match wd any option...
  so ans is {d}
• 9 years agoHelpfull: Yes(0) No(3)
• 44 ( because 68 36 72 will divided by 4, thus 17+9+18=44)
• 8 years agoHelpfull: Yes(0) No(0)