In a family, the father took 1/5 of the cake and he had 4 times as much as others had, then the family members are:
a) '16' b) '17' c) '18' d) 'None of these

• assume that the cake is 100 gm weight. if father took 1/5 then it was 20 gm.the 20 gm cake is 4 times as much as others had, so others took 20/4=5 gm.then for remainig 80 gm of cake there are 16 members.16+ father= 17 members
• 12 years agoHelpfull: Yes(110) No(2)
• b) 17
  
  If there are 'x' members in a family, father took 1/5 of the cake, so remaining 4/5 cake will be distributed among (x-1) members, so each member will get (4/5)/(x-1)
  As 1/5 =4*(4/5)/(x-1)
  x=17
• 8 years agoHelpfull: Yes(14) No(1)
• i need wipro verbal n logical qnos..
• 11 years agoHelpfull: Yes(6) No(12)
• remaining cake=(1-1/5)=4/5
  other each member take=(1/5 )*(1/4)=1/20
  other no of member=(4/5)/(1/20)=16
  total member=16+1=17
• 10 years agoHelpfull: Yes(6) No(6)
• let total cake is 1 and there are x no of member.
  father took 1/5.
  then others took=1 - (1/5)=4/5.
  If we not consider the father then there are (x-1) member and each member took (4/5)/(x-1)=4/5(x-1)
  now as father had 4 times then other,we can write the equation like this,
  1/5 = 4*4/5(x-1)
  or,1/5=16/5(x-1)
  or,x-1=16
  or,x=17
  .'. Total no of member=17.(ans)
  
• 8 years agoHelpfull: Yes(3) No(0)
• 17 members
• 10 years agoHelpfull: Yes(1) No(4)
• 17 it is correct
• 6 years agoHelpfull: Yes(0) No(0)