Capgemini
Company
Numerical Ability
Algebra
If 2 ^ 51?
Read Solution (Total 3)
-
- 2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
2^7 = 128
2^8 = 256
....
last digits are {2,4,8,6...,2,4,8,6} i.e.,for every 4 sets the last digits are repeated so 12*4+3 digits so 2^51 has last digit is "8". - 12 years agoHelpfull: Yes(16) No(0)
- 51/4 -> remainder is 3 ,2^3 = 8
therefore unit's place digit is 8
to find unit's place digit
2^1 = 2,2^2 = 4,2^3 =8,2^4 =6 and again the cycle repeats i.e 2^5 =2
This cycle repeats after 4 period therefore the power is divided by 4. - 12 years agoHelpfull: Yes(8) No(3)
- log2^51=51(log2)=51
- 12 years agoHelpfull: Yes(2) No(54)
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