If 2 ^ 51?

• 2^1 = 2
  2^2 = 4
  2^3 = 8
  2^4 = 16
  2^5 = 32
  2^6 = 64
  2^7 = 128
  2^8 = 256
  ....
  last digits are {2,4,8,6...,2,4,8,6} i.e.,for every 4 sets the last digits are repeated so 12*4+3 digits so 2^51 has last digit is "8".
• 11 years agoHelpfull: Yes(16) No(0)
• 51/4 -> remainder is 3 ,2^3 = 8
  therefore unit's place digit is 8
  to find unit's place digit
  2^1 = 2,2^2 = 4,2^3 =8,2^4 =6 and again the cycle repeats i.e 2^5 =2
  This cycle repeats after 4 period therefore the power is divided by 4.
• 11 years agoHelpfull: Yes(8) No(3)
• log2^51=51(log2)=51
• 11 years agoHelpfull: Yes(2) No(54)