if the circumference of the circle in increased by 50% then its area will be increased by how many sq.cms?

• 125%
  let initaily radius be r
  aftr incremnt it be R
  aftr 50% incremnt in circumfrnc...
  2*3.14*R=1.5*2*3.14*r
  R=1.5r
  % change in area=(3.14*R*R-3.14r*r)/3.14*r*r
  put R=1.5r
  requrd % chnge in area is=125%
  
• 12 years agoHelpfull: Yes(14) No(2)
• C=pi*r
  => 50 % increase in C => 50% increase in r => new r = r+r/2 = 3/2r .
  so
  A'/A= [(r3/2)^2]/r
  => A'/A = 9/4
  => (A'-A)/A = 9/4 - 1
  => (A'-A)/A * 100= 5/4 *100 multiplying boths side by 100
  => (A'-A)/A * 100= 125
  => net % increase in area = 125%
  so area increase can be calculated
• 12 years agoHelpfull: Yes(7) No(2)
• As we know circumference is directly proportional to radius(r) of the circle.
  let, Radius be r cm.
  Increased radius =r * 150/100=3r/2 cm
  Increased in area= pi{(9r^2/4)-r^2}.
  =pi(5r^2)/2 sq. cm
• 12 years agoHelpfull: Yes(5) No(3)
• rakesh kumar plzz send me d latest qstns venkat3191@gmail.com
• 12 years agoHelpfull: Yes(1) No(0)