What is the distance in cm between two parallel chords of lengths 32cm and 24 cm in a circle of radius 20 cm
a)4 or 28
b)3or 21
c)2 or 14
d)1 or 7

• through mid point of one chord draw line segment meeting center point you will get a right angled triangle. solve and find the length of line segment by pythagorus theorem
  for chord 24cm
  20^2-12^2=256=16^2
  do same for the chord 32 cm
  20^2-16^2=144=12^2
  So distance btween them is sum of line segment calculated
  ie 12+16=28
  a is correct
• 9 years agoHelpfull: Yes(13) No(0)
• 32/2=16
  20*20-16*16=144=12^2 so the distance of chord 32cm from center is 12cm
  24/2=12
  20*20-12*12=256=16^2 so the distance of chord 24cm from center is 16cm
  
  hence the distance between these two chords is 16-12=4cm or 16+12=28cm
• 9 years agoHelpfull: Yes(3) No(0)
• Let two chords are AB (32cm) and CD(24cm) and o is the center of circle.
  When a line from center o cuts AB, it divides it into two parts 16cm each known as AP(16cm),PB(16cm)
  then AP =16cm , Ao =20cm and Po=?. which makes it a triangle
  Now by the thm...
  (Ao)^2 = (AP)^2 + (Po)^2 ...... eq 1
  By solving this we get
  Po=12cm
  and similary we get another
  BQ=12, Qo=?, Bo=20cm
  we get Qo=16cm
  by adding Po + Qo= 28 cm
  
• 9 years agoHelpfull: Yes(3) No(0)
• option A
  
  case 1: When the two chords are on the same side
  (20^2-16^2)^1/2=12
  (20^2-12^2)^1/2=16
  Distance between two chords = 16-12=4
  
  Case 2: When they are on opposite side from the centre
  Distance=16+12=28
  
• 9 years agoHelpfull: Yes(1) No(0)
• opt (a) draw the figure and find the angles
• 9 years agoHelpfull: Yes(1) No(0)
• I think answer is 4 or 12.
• 9 years agoHelpfull: Yes(0) No(3)
• hence two chords are parallel to each other in circle.so line joining the mid point a chord to the center produce a right angled triangle ...so tan45=x/16.
  x=16
  same in other chord also tan45=a/12
  a=12
  total length between two chord=16+12=28
• 9 years agoHelpfull: Yes(0) No(0)