for which of the following n is the number 274 +22058+22n is a perfect square?
a)2012 b)2100 c)2011 d)2010

• 2^(2*37) + 2^(2058) + 2^(2n)
  a^2 + 2ab + b^2
  (2^37)2 + (2^n)2 + 2*2^37*2^n
  Here a = 2^37, b = 2^n ,2ab= 2^1*2^37*2^n
  2^(38+n) = 2^(2058)
  38+n =2058
  n = 2020
• 10 years agoHelpfull: Yes(19) No(1)
• dummy question none of the above
• 11 years agoHelpfull: Yes(15) No(11)
• the ques is 2^74 + 2^2058 + 2^2n is a perfect square/
  
• 11 years agoHelpfull: Yes(7) No(14)
• all option are wrong
  
• 11 years agoHelpfull: Yes(5) No(8)
• Ans. 2010
  A perfect square is square with four sides equal.
  274 +22058+22(2010)=66552. For a perfect square divide it by 4. we get 16638. Hence it makes a perfect square with 16638 as one side
• 11 years agoHelpfull: Yes(4) No(4)
• Ans. 2010
  A perfect square is square with four sides equal.
  274 +22058+22(2010)=6652. For a perfect square divide it by 4m. we get 16638. Hence it makes a perfect square
• 11 years agoHelpfull: Yes(3) No(10)
• plz send me recent tcs paper "singh.ashish4nov@gmail.com" its urgent..
• 11 years agoHelpfull: Yes(2) No(12)
• plz... send me recent tcs paper with solution..email:himanshujain8888@gmail.com
• 11 years agoHelpfull: Yes(1) No(2)
• Answer is 2020
  
  soln: (a+b)^2 = a^2 + b^2 + 2*a*b
  
  => (2^37)^2 + (2^n)^2 + 2*2^37*2^2020
  so n=2020
• 10 years agoHelpfull: Yes(1) No(1)
• (a+b)^2 is a perfect square.
  so, (2^37)^2+(2*2^37*2^n)+(2^n)^2.
  2^37*2^n*2=2^2058
  n=2020
• 9 years agoHelpfull: Yes(0) No(0)