Let N be the greatest number that
divides 1305, 4665 and 6905, leaving the
same remainder in each case. Then sum of
the digits in N is:
a) 4 b) 5
c) 6 d) 8

• HCF of (4665-1305) , ( 6905-4665) , (6905-1305)
  
  = HCF of 3360 ,2240,5600
  
  = 1120
  
  sum of digits = 4
• 9 years agoHelpfull: Yes(13) No(4)
• HCF of (4665-1305) , ( 6905-4665) , (6905-1305)
  
  = HCF of 3360 ,2240,5600
  
  = 1120
  
  sum of digits = 4
• 9 years agoHelpfull: Yes(0) No(0)