How many 4 digit numbers can be formed using the digits 1,2,3,4,5 (but without repetition) that are divisible by 4

• Numbers to be divisible divisible by 4 must have 12 or 24 or 32 or 52 at the last 2 places(since the given digits are 1,2,3,4,5). So the last places are fixed and only 2 places are left, we have 3 digits to fill the two places and since repetition is not allowed, we have 3 ways to fill 1st place and 2 ways to fill 2nd place. So 3*2*4=24 is the answer
  
• 9 years agoHelpfull: Yes(22) No(3)
• check the no. divide by 4 which can take last two place.
  that is 12,24,32 and 52. other place are filled by 3!
  ans is 3!*4=24
• 9 years agoHelpfull: Yes(7) No(3)
• the last two divisible by 4 are 12 ,24 ,32,and 52. in all cases we fixed last 2 digits and remaining 2 digits can be selected as 3c2........and it is repeated for 4 times so ans. is 4*3c2= 12
  
• 9 years agoHelpfull: Yes(3) No(3)
• plz send me the tcs mock test papers with solution to ankitjayswal24@gmail.com 20th feb 2015 is my written test of tcs so plz help me guyz....
• 9 years agoHelpfull: Yes(2) No(0)
• divisible by 4 must have 12 , 24 , 32 , 44 and 52 at the last 2 places(since the given digits are 1,2,3,4,5).and left 3 digit can 3!=6 (without repetition)so ans 6*5=30 ways .i hope its r8 ans.
  
• 9 years agoHelpfull: Yes(2) No(2)
• 24
  The last two digits can be only 12, 2, 52, 32.(4 in no)
  The possible combinations of the remaining places is 3*2 = 6
  Hence 6*4 = 24
• 9 years agoHelpfull: Yes(2) No(1)
• divisible by 4 it means last two digit should be devisible by 4 in that 4 digit number.
  so we 5 diffrent digit and we have to form that number without repetition so at last position number of combination possible is 12 24 32 52 so last to boxes is fixed means 4 and two digits are used so 3 digit left 4*3*2 total 24 combination possible .(m not sure)
• 9 years agoHelpfull: Yes(1) No(2)
• 5*4*3*4=240
• 9 years agoHelpfull: Yes(0) No(5)