1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,1,1,1,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,4,......... in the above sequence what is the number at the position 2888 of the sequence.

• answer is-3
  First if we count 1223334444. they are 10
  In the next term they are 20
  Next they are 30 and so on
  
  now I have opted for a manual process
  so, the 23rd repetition will end at 2760 position (using formula (n*(first term +last term)/2), now the 24th repetition will start and 1 will be repeated 24 times i.e at position 2760+24=2784 ,similarly repetition of digit 2 will start and it will be repeated 48 times and will end up at position 2784+48=2832,
  now finally digit 3 will start and will be repeated 72 time i.e at position 2888 digit 3 will be present.
• 9 years agoHelpfull: Yes(31) No(2)
• answer:1
  in first set 1 repeat 1 time, 2 repeat 2 times, 3 repeat 3 times and 4 repeat 4 times and in next set every number repeats der mutiples of 1, 2,3,4,5,6..... so on
  at 100th set:1*100+2*100+3*100+4*100=1000 i.e at 1000 sequence 4 is d num
  at 288th set: 1*288+2*288+3*288+4*288=2880 i.e at 2880 sequence 4 is d num
  and the next num is 1(i.e num 1 starts from 2881) repeats for 299 times so answer is 1
• 9 years agoHelpfull: Yes(9) No(8)
• ans:3
  for first set(1223334444) the no. of terms are 10
  next set - 20
  next- 30
  total number of terms after 2nd set = 10+20
  similarly total number of terms after 4 sets = 10+20+30+40
  similarly total number of terms after n sets = (n(n+1)/2)*10
  if we take n=23 number of terms=2760
  in 24 set 1 is repeated 24 times,so 2760+24=2784
  2 is repeated 48 times, 2784+48=2832; 3 is repeated 72 times,so at 2888 position 3 is present
• 9 years agoHelpfull: Yes(7) No(0)
• 4 is the number at the position 2888 of the sequence.
  
• 9 years agoHelpfull: Yes(4) No(7)
• answer is 3
• 9 years agoHelpfull: Yes(4) No(0)
• answer is 3
  
  battery ....whatsapp pe smjh liyo ! :p
• 9 years agoHelpfull: Yes(2) No(7)
• For the whole solution please check Discussion Board
  As my whole solution is not showing here.
• 9 years agoHelpfull: Yes(2) No(0)
• First if we count 1223334444. they are 10
  In the next term they are 20
  Next they are 30 and so on
  So,
  Using { n(n+1)/2 } × 10
• 9 years agoHelpfull: Yes(1) No(2)
• First if we count 1223334444. they are 10
  In the next term they are 20
  Next they are 30 and so on
  So,
  Using {n(n+1) / 2} × 10
• 9 years agoHelpfull: Yes(1) No(2)
• answer is 3
  
• 9 years agoHelpfull: Yes(1) No(1)
• 4 is correct
• 9 years agoHelpfull: Yes(1) No(1)
• 1 is correct........Lakshmi Y is absolutely right
• 9 years agoHelpfull: Yes(1) No(0)
• the series is the order of 10 20 30....
  so last digit divides by 10 nearer to 2888 is 2880
  so next series will be 11111111....
  so answer is 1 exactly
• 9 years agoHelpfull: Yes(1) No(0)
• @sushant plz explain the method
• 9 years agoHelpfull: Yes(0) No(0)
• please explain the answer???
• 9 years agoHelpfull: Yes(0) No(0)
• Sorry for the 1st submission,
  First if we count 1223334444. they are 10
  In the next term they are 20
  Next they are 30 and so on
  So,
  Using n(n+1)/2 × 10
• 9 years agoHelpfull: Yes(0) No(0)
• First if we count 1223334444. they are 10
  In the next term they are 20
  Next they are 30 and so on
  so using the formula
  n(n+1)/2 * 10
• 9 years agoHelpfull: Yes(0) No(0)
• so using the formula
  n(n+1)/2 * 10
• 9 years agoHelpfull: Yes(0) No(0)
• 1st if we count 1223334444
  they are 10
  in the next term they are 20
  next they are 30 and so on
  so using the formula
  n(n+1)/2 * 10
• 9 years agoHelpfull: Yes(0) No(0)
• n(n+1)/2 * 10
• 9 years agoHelpfull: Yes(0) No(0)
• 1st if we count 1223334444
  they are 10
  in the next term they are 20
  next they are 30 and so on
  so using the formula
  n(n+1)/2 * 10
• 9 years agoHelpfull: Yes(0) No(0)
• 1st if we count 1223334444
  they are 10
  in the next term they are 20
  next they are 30 and so on
  so using the formula
  n(n+1)/2 * 10
• 9 years agoHelpfull: Yes(0) No(0)
• 3 is correct
• 9 years agoHelpfull: Yes(0) No(0)
• pls xplain what is n in n(n+1)/2*10
• 9 years agoHelpfull: Yes(0) No(0)
• 722 is anwser....
• 9 years agoHelpfull: Yes(0) No(2)
• 3
  i think the series will be like this 10 20 40 80 160 so the last series will be 2560 so the num is 3
• 9 years agoHelpfull: Yes(0) No(1)
• Thnku Tej..
• 9 years agoHelpfull: Yes(0) No(0)
• Using n(n+1)/2×10≤2888
  For n = 23 we get LHS as 2760. Remaining terms 128.
  Now in the 24th term, we have 24 1's, and next 48 terms are 2's. So next 72 terms are 3's.
  
  The 2888 term will be “3”.
• 5 years agoHelpfull: Yes(0) No(0)
• In 1 set(1,2,2,3,3,3,4,4,4,4)
  1=1time
  2=2times
  3=3times
  4=4 times
  Clearly sum of all no is 10
  And similarly in another set total no is 20
  And so on
  Clearly[ n(n+1)/2]*10
  And put n=23
  n=2760
  But we get 2880
  Clearly for n=24..... 1 will 24 times so
  2760+24=2784
  2 will 48 times so
  2784+48=2868
  3will 72 times
  Clearly 3 will answer
• 4 years agoHelpfull: Yes(0) No(0)