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N! Is having 37 zeroes at its end. How many values of N is/are possible?
a) 0 b) 1 c) 5 d) Infinite

Read Solution (Total 3)

N can have values from 150 to 154

so 5 values of N are possible.
12 years agoHelpfull: Yes(11) No(5)

plz explain clearly
12 years agoHelpfull: Yes(0) No(2)
Take the number that you've been given the factorial of.
Divide by 5; if you get a decimal, truncate to a whole number.
Divide by 52 = 25; if you get a decimal, truncate to a whole number.
Divide by 53 = 125; if you get a decimal, truncate to a whole number.
Continue with ever-higher powers of 5, until your division results in a number less than 1. Once the division is less than 1, stop.
Sum all the whole numbers you got in your divisions. This is the number of trailing zeroes.
11 years agoHelpfull: Yes(0) No(2)

TCS Other Question

An intelligence agency forms a code of two distinct digits selected from 0, 1,....,9 such that the first digit of the code is non-zero. The code, handwritten on a slip, however, can potentially create confusion when read upside down, e.g. the code 91 may appear as 16. How many codes are there for which no such confusion can arise?
a) 80 b) 63 c) 71 d) None of these
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