In a forest reserve, the ratio of the number of deers, bear and fox is 3 : 7 : 5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?
a) 315 b) 310 c) 45 d) None of these

• 7-3=4, but the difference is a multiple of 3 and 7, therefore 4*3*7=84
  if 4 corresponds to 84 then
  3+7+5 corresponds to 315
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• a ) ....315 is correct
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• none o these...7-3=4..4 isnt a multiple of three..so it doesnt satisfy the 2nd condition..
  
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• can u pls explain clearly
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