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N is natural no. N^3 can have maximum 16 factors then how many maximum factors can N^4 have?

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lets say a term 6
Now 6^3=(2^3 )* (3^3)
so, no of factors=(3+1)*(3+1)=16(using prime factorization)
Now similarly
6^4=(2^4)*(3^4)
so factors, (4+1)*(4+1)= 25
So the ans is 25.
11 years agoHelpfull: Yes(22) No(3)

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